167. Two Sum II - Input array is sorted
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.
Note:
Your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution and you may not use the same element twice.
Example:
Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.
Solution
因為sort過,可以使用two pointer的方式來縮小range
public int[] twoSum(int[] numbers, int target) {
int lo = 0, hi = numbers.length - 1;
while(lo < hi){
if(target == numbers[lo] + numbers[hi]){
return new int[]{lo+1, hi+1};
}
else if( target > numbers[lo] + numbers[hi]){
lo++;
}
else
hi--;
}
return new int[]{0,0};
}
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