135. Candy
There are n
children standing in a line. Each child is assigned a rating value given in the integer array ratings
.
You are giving candies to these children subjected to the following requirements:
Each child must have at least one candy.
Children with a higher rating get more candies than their neighbors.
Return the minimum number of candies you need to have to distribute the candies to the children.
Example 1:
Input: ratings = [1,0,2]
Output: 5
Explanation: You can allocate to the first, second and third child with 2, 1, 2 candies respectively.
Example 2:
Input: ratings = [1,2,2]
Output: 4
Explanation: You can allocate to the first, second and third child with 1, 2, 1 candies respectively.
The third child gets 1 candy because it satisfies the above two conditions.
Constraints:
n == ratings.length
1 <= n <= 2 * 104
0 <= ratings[i] <= 2 * 104
Solution
Fill in the candy array in two directions.
For each direction, we only consider the neighbor from (left/right) sides.
public int candy(int[] ratings) {
int n = ratings.length;
int ret = 0;
int[] candy = new int[n];
for(int i = 0; i < n; i++){
candy[i] = 1;
}
for(int i = 1; i < n; i++){
if(ratings[i] > ratings[i-1]){
candy[i] = candy[i-1]+1;
}
}
for(int i = n-2; i >= 0; i--){
if(ratings[i] > ratings[i+1]){
candy[i] = Math.max(candy[i+1]+1, candy[i]);
}
}
for(int num : candy){
ret+=num;
}
return ret;
}
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