242. Valid Anagram
Given two strings s and t , write a function to determine if t is an anagram of s.
Example 1:
Input: s = "anagram", t = "nagaram"
Output: true
Example 2:
Input: s = "rat", t = "car"
Output: false
Note: You may assume the string contains only lowercase alphabets.
Follow up: What if the inputs contain unicode characters? How would you adapt your solution to such case?
Soltution
概念上也是去紀錄每個字母的是用狀態,直覺上會想到hashMap。
但其實若是input有限制是26個英文字母的話,用array就夠了
public boolean isAnagram(String s, String t) {
if(s.length() != t.length()){
return false;
}
int[] alphabet = new int[26];
for(int i = 0; i < s.length(); i++){
alphabet[s.charAt(i) - 'a']++;
alphabet[t.charAt(i) - 'a']--;
}
for(int i : alphabet){
if(i != 0){
return false;
}
}
return true;
}
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