843. Guess the Word
This is an interactive problem.
You are given an array of unique strings wordlist
where wordlist[i]
is 6
letters long, and one word in this list is chosen as secret
.
You may call Master.guess(word)
to guess a word. The guessed word should have type string
and must be from the original list with 6
lowercase letters.
This function returns an integer
type, representing the number of exact matches (value and position) of your guess to the secret
word. Also, if your guess is not in the given wordlist, it will return -1
instead.
For each test case, you have exactly 10
guesses to guess the word. At the end of any number of calls, if you have made 10
or fewer calls to Master.guess
and at least one of these guesses was secret
, then you pass the test case.
Example 1:
Input: secret = "acckzz", wordlist = ["acckzz","ccbazz","eiowzz","abcczz"], numguesses = 10
Output: You guessed the secret word correctly.
Explanation:
master.guess("aaaaaa") returns -1, because "aaaaaa" is not in wordlist.
master.guess("acckzz") returns 6, because "acckzz" is secret and has all 6 matches.
master.guess("ccbazz") returns 3, because "ccbazz" has 3 matches.
master.guess("eiowzz") returns 2, because "eiowzz" has 2 matches.
master.guess("abcczz") returns 4, because "abcczz" has 4 matches.
We made 5 calls to master.guess and one of them was the secret, so we pass the test case.
Example 2:
Input: secret = "hamada", wordlist = ["hamada","khaled"], numguesses = 10
Output: You guessed the secret word correctly.
Constraints:
1 <= wordlist.length <= 100
wordlist[i].length == 6
wordlist[i]
consist of lowercase English letters.All the strings of
wordlist
are unique.secret
exists inwordlist
.numguesses == 10
Solution
The key is to narrow the searching interval.
Given that the secret will be in the list.
So, when we make a guess with a word (called it guessWord).
We can look over the list by checking the word's matches count between this word and the guessWord.
If the matches count is equal to the matches which get from the Master.guess(guessWord) function.
Then, this word is likely to be the secret, we can make a guess with it next round.
We repeated the aboved step to make a good guess.
class Solution {
public void findSecretWord(String[] wordlist, Master master) {
for(int i = 0; i < 10; i++){
String guessWord = wordlist[(new Random()).nextInt(wordlist.length)];
int matches = master.guess(guessWord);
if(matches == 6) break;
List<String> newWordList = new ArrayList<>();
for(String word : wordlist){
if(word != guessWord && isMatches(guessWord, word, matches)){
newWordList.add(word);
}
}
wordlist = newWordList.toArray(new String[newWordList.size()]);
}
}
public boolean isMatches(String w1, String w2, int matches){
int count = 0;
for(int i = 0; i < 6; i++){
if(w1.charAt(i) == w2.charAt(i)) {
count++;
}
}
return count == matches;
}
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